Solving math problems online is an ideal way to learn math conveniently and simply. Make the most of the online resources at your disposal and find excellent math problem solvers for free.

**Solve math problems**with no difficulty and start using online math helpers who make learning math simple and engaging. Math websites which offer help with math problems are comprehensive and cover arithmetic, algebra, trigonometry, matrices and lots more. Students of every grade will find help with math problems and all the topics that are taught in class. Many math help websites also have free math problems to enable students to practice what they learn.Let us discuss some examples of equations:

### Solved Examples

**Question 1:**Solve for x, 2x - 7 = 9

**Solution:**

Given 2x - 7 = 9

Add 7 both side

2x - 7 + 7 = 9 + 7

=> 2x = 16

Divide each side by 2

=> $\frac{2x}{2}$ = $\frac{16}{2}$

Add 7 both side

2x - 7 + 7 = 9 + 7

=> 2x = 16

Divide each side by 2

=> $\frac{2x}{2}$ = $\frac{16}{2}$

**=> x = 8, is the answer.****Question 2:**Solve x

^{2}- x - 6

**Solution:**

Given x

Factorized given equation,

x

= x(x - 3) + 2(x - 3)

= (x + 2)(x - 3)

Hence x

^{2}- x - 6, is a quadratic equation.Factorized given equation,

x

^{2}- x - 6 = x^{2}- 3x + 2x - 6= x(x - 3) + 2(x - 3)

= (x + 2)(x - 3)

Hence x

^{2}- x - 6 = (x + 2)(x - 3)**Question 3:**Find the value of p, 2p + 3x - 4 = 5, for x = 1.

**Solution:**

Given, 2p + 3x - 4 = 5 .................(1)

Put x = 1 in equation (1)

=> 2p + 3(1) - 4 = 5

=> 2p + 3 - 4 = 5

=> 2p -1 = 5

=> 2p = 5 + 1

=> 2p = 6

=> p = $\frac{6}{2}$ = 3

Put x = 1 in equation (1)

=> 2p + 3(1) - 4 = 5

=> 2p + 3 - 4 = 5

=> 2p -1 = 5

=> 2p = 5 + 1

=> 2p = 6

=> p = $\frac{6}{2}$ = 3

**=> p = 3, is the answer.**The internet is a huge resource for math problems-both solved and unsolved. Students will find plenty of opportunity to practice their math problem solving skills with worksheets covering every type of question. The answers are provided and you will also find solved examples which provide a template for how the problems need to be solved. For students trying to improve their understanding of the subject, unsolved math problems will give you the challenge you need.

### Solved Example

**Question:**The perimeter of a rectangle with length 6m is 16m. Find the area of the rectangle.

(In this statement, it is quit difficult to find the answer directly, but not impossible. For that you have the knowledge of area and perimeter of the rectangle.)

**Solution:**

Given

Length of a rectangle = 6

Perimeter = 16

We know,

Perimeter of rectangle = 2(length + width)

Area of rectangle = length x width

According to statement,

2(length + width) = 16

=> 2(6 + width) = 16

=> 6 + width = 8

=> width = 8 - 6

=> width = 2m

Again

Area = 6 x 2 = 12

Length of a rectangle = 6

Perimeter = 16

We know,

Perimeter of rectangle = 2(length + width)

Area of rectangle = length x width

According to statement,

2(length + width) = 16

=> 2(6 + width) = 16

=> 6 + width = 8

=> width = 8 - 6

=> width = 2m

Again

Area = 6 x 2 = 12

**=> Area of rectangle is 12m**^{2}.