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Let us discuss some examples of equations:

Given 2x - 7 = 9

Add 7 both side

2x - 7 + 7 = 9 + 7

=> 2x = 16

Divide each side by 2

=> $\frac{2x}{2}$ = $\frac{16}{2}$

**=> x = 8, is the answer.**

Add 7 both side

2x - 7 + 7 = 9 + 7

=> 2x = 16

Divide each side by 2

=> $\frac{2x}{2}$ = $\frac{16}{2}$

Given x^{2} - x - 6, is a quadratic equation.

Factorized given equation,

x^{2} - x - 6 = x^{2} - 3x + 2x - 6

= x(x - 3) + 2(x - 3)

= (x + 2)(x - 3)

Hence x^{2} - x - 6 = (x + 2)(x - 3)

Factorized given equation,

x

= x(x - 3) + 2(x - 3)

= (x + 2)(x - 3)

Hence x

Given, 2p + 3x - 4 = 5 .................(1)

Put x = 1 in equation (1)

=> 2p + 3(1) - 4 = 5

=> 2p + 3 - 4 = 5

=> 2p -1 = 5

=> 2p = 5 + 1

=> 2p = 6

=> p = $\frac{6}{2}$ = 3

**=> p = 3, is the answer.**

Put x = 1 in equation (1)

=> 2p + 3(1) - 4 = 5

=> 2p + 3 - 4 = 5

=> 2p -1 = 5

=> 2p = 5 + 1

=> 2p = 6

=> p = $\frac{6}{2}$ = 3

The internet is a huge resource for math problems-both solved and unsolved. Students will find plenty of opportunity to practice their math problem solving skills with worksheets covering every type of question. The answers are provided and you will also find solved examples which provide a template for how the problems need to be solved. For students trying to improve their understanding of the subject, unsolved math problems will give you the challenge you need.

Solved Example

(In this statement, it is quit difficult to find the answer directly, but not impossible. For that you have the knowledge of area and perimeter of the rectangle.)

Given

Length of a rectangle = 6

Perimeter = 16

We know,

Perimeter of rectangle = 2(length + width)

Area of rectangle = length x width

According to statement,

2(length + width) = 16

=> 2(6 + width) = 16

=> 6 + width = 8

=> width = 8 - 6

=> width = 2m

Again

Area = 6 x 2 = 12

**=> Area of rectangle is 12m**^{2} .

Length of a rectangle = 6

Perimeter = 16

We know,

Perimeter of rectangle = 2(length + width)

Area of rectangle = length x width

According to statement,

2(length + width) = 16

=> 2(6 + width) = 16

=> 6 + width = 8

=> width = 8 - 6

=> width = 2m

Again

Area = 6 x 2 = 12