7th grade math covers a variety of topics in mathematics like integers and rational numbers, basic geometry, probability and statistics and pre-algebra. Students who finish 7th grade math are expected to be able to cope with a full fledged algebra course, which they will begin in high school. It’s a crucial year and any confusion that students leave with may well remain for the next five years. Learning math is simple, provided you know where to go for help. Today the Internet is replete with math help sites offering help with the most basic to college level math. Look at a few math websites and you will find lots of 7th grade math problems with answers. With online math helpers, you will always have enough and more 7th grade math practice problems to work on. These practice worksheets contain all types of questions that you will cover in class and be asked on tests. The easy accessibility and 24x7 availability of study material have made
the Internet a popular study tool for scores of students everywhere.

Given, Riffela travel 30 miles in two hours

Let he traveled 'd' miles in 4 hours.

=> $\frac{30}{2} = \frac{d}{4}$

=> 15 = $\frac{d}{4}$

=> 15 * 4 = d

=> 60 = d

=> Hence, Riffela traveled 60 miles in 4 hours.

Let he traveled 'd' miles in 4 hours.

=> $\frac{30}{2} = \frac{d}{4}$

=> 15 = $\frac{d}{4}$

=> 15 * 4 = d

=> 60 = d

=> Hence, Riffela traveled 60 miles in 4 hours.

Base of triangle = 5

Height = 12

[Area of triangle = $\frac{1}{2}$base x height]

=> Area of triangle = $\frac{1}{2}$ x 5 x 12

= 30

=> Area of triangle = 30 square mtr.

Height = 12

[Area of triangle = $\frac{1}{2}$base x height]

=> Area of triangle = $\frac{1}{2}$ x 5 x 12

= 30

=> Area of triangle = 30 square mtr.

Total Balls = 12

Red Balls = 5

Green Balls = 2

Blue Balls = 5

Let the probability of getting a red or a blue ball = A

=> P(A) = $\frac{Number of Favorable Outcomes}{Total Numbers of Outcomes}$

=> P(A) = $\frac{5 + 5}{12}$

= $\frac{10}{12}$

= $\frac{5}{6}$

=> Probability of getting a red or a blue ball = $\frac{5}{6}$.

Red Balls = 5

Green Balls = 2

Blue Balls = 5

Let the probability of getting a red or a blue ball = A

=> P(A) = $\frac{Number of Favorable Outcomes}{Total Numbers of Outcomes}$

=> P(A) = $\frac{5 + 5}{12}$

= $\frac{10}{12}$

= $\frac{5}{6}$

=> Probability of getting a red or a blue ball = $\frac{5}{6}$.