A few years back, the only math problem solvers students could depend on were their math teachers. Times have changed and the internet is fast changing the way students learn. From online tutorials to virtual class rooms, the World Wide Web is revolutionizing education. Easily accessible with flexible schedules, online education is growing in popularity. Many students log on everyday to get help with lessons, homework and even engage with a live tutor for a tutoring session. College students will find online math solvers a very handy tool that covers everything that you will learn in college as well as high school math and algebra. This is great in case you ever need to refresh your memory.

## Math Problems Solver

### Solved Examples

**Question 1:**Find the value of 'a' at x = 2 .

$\sqrt{2x + 3a}$ = 5

**Solution:**

Step 1:

Given equation

$\sqrt{2x + 3a}$ = 5

Step 2:

Squaring both side to remove the radical

=> 2x + 3a = 25

=> 3a = 25 - 2x ......................(1)

Step 3:

Substituting x = 2 in equation (1),

=> 3a = 25 - 2 * 2

=> 3a = 25 - 4 = 21

=>

Given equation

$\sqrt{2x + 3a}$ = 5

Step 2:

Squaring both side to remove the radical

=> 2x + 3a = 25

=> 3a = 25 - 2x ......................(1)

Step 3:

Substituting x = 2 in equation (1),

=> 3a = 25 - 2 * 2

=> 3a = 25 - 4 = 21

=>

**a = 7****Question 2:**Solve quadratic equation 6x

^{2}+ 25x - 25 = 0

**Solution:**

Given quadratic equation 6x

=> 6x

Factors the left hand side of the equation,

=> 6x

=> 6x(x + 5) - 5(x + 5) = 0

=> (6x - 5)(x + 5) = 0

=> either 6x - 5 = 0 or x + 5 = 0

=> 6x = 5

=> x = $\frac{5}{6}$

or x = - 5

=> Solutions of equation are

^{2}+ 25x - 25 = 0=> 6x

^{2}+ 25x - 25 = 0Factors the left hand side of the equation,

=> 6x

^{2}+ 30x - 5x - 25 = 0=> 6x(x + 5) - 5(x + 5) = 0

=> (6x - 5)(x + 5) = 0

=> either 6x - 5 = 0 or x + 5 = 0

=> 6x = 5

=> x = $\frac{5}{6}$

or x = - 5

=> Solutions of equation are

**x = 0.83, - 5.****Question 3:**Solve the system of equations

- 3 + 5x = y

2x + 5y = 12

**Solution:**

Given

- 3 + 5x = y

2x + 5y = 12

or

5x - y = 3 ................(1)

2x + 5y = 12 ...............(2)

No equation given solved for a variable, Equation (1) can be solved literal for y,

y = 5x - 3

Substituting the expression in equation (2)

=> 2x + 5(5x - 3) = 12

=> 2x + 25x - 15 = 12

=> 27x - 15 = 12

=> 27x = 12 + 15 = 27

=> x = 1

Substituting x = 1 in y = 5x - 3,

y = 5 x 1 - 3 = 5 - 3 = 2

=> y = 2

Hence the solution to the given system,

- 3 + 5x = y

2x + 5y = 12

or

5x - y = 3 ................(1)

2x + 5y = 12 ...............(2)

Step 1:Step 1:

No equation given solved for a variable, Equation (1) can be solved literal for y,

y = 5x - 3

Substituting the expression in equation (2)

=> 2x + 5(5x - 3) = 12

=> 2x + 25x - 15 = 12

=> 27x - 15 = 12

=> 27x = 12 + 15 = 27

=> x = 1

Step 2:Step 2:

Substituting x = 1 in y = 5x - 3,

y = 5 x 1 - 3 = 5 - 3 = 2

=> y = 2

Hence the solution to the given system,

**x = 1 and y = 2.**## Math Solver Word Problems

### Solved Examples

**Question 1:**The length of a rectangle is 20 more than twice is width. If the perimeter is 280 feet, how wide is the rectangle.

**Solution:**

Let width of the rectangle = x

then length = 2x + 20

(Length be 20 more than twice its width)

Perimeter = 280

We know, Perimeter of rectangle = 2(length + width)

=> 2(length + width) = 280

=> 2(2x + 20 + x) = 280

=> 2(3x + 20) = 280

=> 6x + 40 = 280

=> 6x = 240

=> x = 40 feet

=> Width of the rectangle = 40 feet.

then length = 2x + 20

(Length be 20 more than twice its width)

Perimeter = 280

We know, Perimeter of rectangle = 2(length + width)

=> 2(length + width) = 280

=> 2(2x + 20 + x) = 280

=> 2(3x + 20) = 280

=> 6x + 40 = 280

=> 6x = 240

=> x = 40 feet

=> Width of the rectangle = 40 feet.

**Question 2:**Macshon is now twice as old as Stefy, but five years ago, he was three times as old as she was. How old is Macshon now.

**Solution:**

Let the present age of Stefy = x

Macshon is twice as old as Stefy

=> Age of Macshon = 2x

Age of Stefy = x - 5

and age of Macshon = 2x - 5

The problem states:

Macshon three times as old as Stefy was

=> 2x - 5 = 3(x - 5 )

=> 2x - 5 = 3x - 15

=> x = 10, age of Stefy

So age of Macshon = 2 * 10 = 20

Macshon is twice as old as Stefy

=> Age of Macshon = 2x

**Five years ago:**Age of Stefy = x - 5

and age of Macshon = 2x - 5

The problem states:

Macshon three times as old as Stefy was

=> 2x - 5 = 3(x - 5 )

=> 2x - 5 = 3x - 15

=> x = 10, age of Stefy

So age of Macshon = 2 * 10 = 20

Hence Macshon is of 20.Hence Macshon is of 20.